Just Wonderin?

Question

Anyone got any ideas of how to solve

2^x - x^2 = 0 ?

I already have the solutions...so dont just tell me them...i want methods

Answer 1

I did it this way:

2^x = x^2
x*ln(2) = 2*ln(x)
x/ln(x) = 2/ln(2)
Therefore x = 2.

You can take any base. Since x/ln(x) is unique function this is the only solution.