When you bounce a ball off a hard surface, the height of its bounce depends on its ability to store energy efficiently. The ball has a certain amount of energy when it begins its fall and the more of that energy it can retain, the higher it will bounce. This energy changes forms several times during the bounce, from gravitational potential energy (energy stored in the force of gravity) while it’s up high, to kinetic energy (energy of motion) as it falls, to elastic potential energy (energy stored in the ball’s structure) as it pushes against the ground, to kinetic energy as it rebounds, to gravitational potential energy as it returns to its peak height. Critical to the height of its rebound is the conversion of energy to and from elastic potential energy. In a ball that stores energy efficiently, very little energy is wasted in these conversions. But in a ball that doesn’t bounce well, much or even most of the energy is turned into thermal energy and is lost to the motion of the ball. Instead of bouncing back to great height, the ball gets warmer and bounces feebly.
A well-inflated basketball stores energy in the compression of the air inside it. Air is highly elastic and stores energy efficiently. Its tightly packed air allows the ball to bounce well. But air provides only a small fraction of the energy storage in an under-inflated basketball. Instead, the ball’s leathery skin receives most of the energy during the bounce and it does a poor job of storing that energy. Like a leather belt, the ball’s skin isn’t very elastic and most of the energy given to it by bending is quickly wasted as thermal energy. Thus a firm, well-inflated basketball bounces well while on that isn’t properly inflated bounces weakly
2007-02-17 23:14:17
·
answer #1
·
answered by Jay S 5
·
0⤊
0⤋
a ball bounces because of the kinetic energy transforming into elastic energy. in a hard surface this becomes an elastic collision at its best, since minimal energy is lost because its in a hard surface.
in a soft surface the kinetic energy that the ball has gets lost when it 'collides' with the soft surface, and instead of bouncing back up it deforms the surface dissipating the elastic potential energy.
hope that helps, im sorry but thats all a yr 12 physics student can tell you, in their own words :P
2007-02-17 23:15:16
·
answer #2
·
answered by Wilson J 4
·
0⤊
0⤋
A rubber ball hits a hard surface and ricochets off the surface. If it hits a soft surface the same thing happens except the soft surface is pushed in a little slowing down the ball.
2007-02-17 23:13:18
·
answer #3
·
answered by Gone fishin' 7
·
0⤊
0⤋
when the ball hits a soft surface, the impulse is absorbed by the soft surface.
when it hits a hard surface the potential and kinetic energy of the ball is transformed into elastic potential energy. the impuls of the ball is not absorbed by the hard surface, thus the ball bounces off.
2007-02-17 23:16:33
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
two thing happen 1 rate of change of moment of ball is faster in case reactin from hard surface
-2- conervation of liner momentum obeyincase hard surface itt act as elastic body & energy loss during collision can be negligible but a cusion surface act as plastic body &time change momemtum is larger is suficient to make ball zero equvalent
2007-02-18 04:43:48
·
answer #5
·
answered by rgfmss 2
·
0⤊
0⤋
this relies upon frequently on the trajectory and organic terrain. In theory, the compression of the two the floor and cannonball would act like a Hook's regulation spring inflicting a "leap". effectively, this would be confusing to get nonetheless- cannonballs do no longer compress very plenty and maximum styles of terrain will deplete the strain of return and forth on impact. So- if all the momentum grow to be no longer absorbed via preliminary impact (i.e. turns into imbedded), then confident it relatively is attainable for a cannonball to leap on inflicting greater mayhem.
2016-10-15 22:25:59
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
when a ball hit ground it deforms and that elastic deformation gets back forcing the ball agianst the ground
every material have a rebound cooffeciant the original hight u through from devided by rebound hight
2007-02-17 23:18:02
·
answer #7
·
answered by koki83 4
·
0⤊
0⤋
remember Newton 3rd Law
2007-02-18 01:13:48
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋
because the ball is made of rubber.
2007-02-18 00:03:33
·
answer #9
·
answered by pa r 1
·
0⤊
0⤋
because every action has an equal and opposite reaction.
2007-02-18 17:13:20
·
answer #10
·
answered by ikkie 2
·
0⤊
0⤋