Need help with quadratics (revised)?

Question

If one root of the quadratic equation x^2-kx-2=0 is 2, find the value of k and the other root. here is what i have so far. am i on the right track.

sorry about the other question the known root is 2

Answer 1

Given that one of the root is 2

substituting it in the given equation,since,it is a root,it should satisfy the equation
so,2^2-k*2-2=0
i.e.,4-2k-2=0
i.e.,2-2k=0
therefore 2k=2
i.e., k=1
now substitute this in the eq i.e., in the given one(x^2-Kx-2=0)

now the eq will be x^2-x-2=0
now by factorization
x^2-2x+x-2=0
i.e., x(x-2)+1(x-2)=0
i.e.,(x+1)(x-2)=0
solving them x=-1 ,2