what are the products of FeO+H2SO4+KMnO4?

Answer 1

This is a redox reaction.

The FeO --> Fe2O3 (Iron II is oxidized to Iron III)
The MnO4- --> Mn+2 (Manganese +7 reduced to Manganese +2)

The balanced equation would be something like:

10 FeO + 3 H2SO4 + 2 KMnO4 --> 5 Fe2O3 + 2 MnSO4 + K2SO4 + 3 H2O

If the Sulfuric acid was in great excess then the FeO would react with it first giving:

FeO + H2SO4 --> FeSO4 + H2O and the final equation would be:

10 FeSO4 + 2 KMnO4 + 8 H2SO4 --> 5 Fe2(SO4)3 + 2 MnSO4 + K2SO4 + 8 H2O

I would list the products as
Iron (III) oxide or sulfate
Manganese (II) sulfate
Potassium Sulfate
and Water.

Answer 2

The FeO(iron oxide, solid) will dissolve in the H2SO4(sulphuric acid, solution), creating a solution of FeSO4( iron sulphate - solution).The KMnO4 (potassium permanganate solution) will need to be acidified, the solution will then oxidise the (iron 2+)Fe2+ ions to Fe3+(iron 3+) Dont know if this answer is any different to the above answer but I tried!