use binomial theorem to evaluate 1.9^3?

Question

Hint: use 1.9 = (2.0 - 0.1)

Answer 1

Use the equation (2-x)^3. Expand this to get (2-x)^3 = 8 - 12x + 6x^2 - x^3. Then set x = 0.1 to get the answer.

Answer 2

Using binomial expansion of (2.0 - 0.1)³ gives us:
2.0³ - (3)(2.0)²(0.1) + (3)(2.0)(0.1)² - (0.1)³

From here, it's easy to do the calculations by hand:

8 - 1.2 + 0.06 - 0.001 =
8.06 - 1.201 = 6.859

Answer 3

(A-B)^3= A^3 - 3A^2.B + 3 A.B^2 - B^3 LET A= 2 B= 0.1