how many moles of oxygen atoms are in 10g of ammonium sulphate?
2007-02-17 20:57:56 · 5 answers · asked by get_xed 1 in Science & Mathematics ➔ Chemistry
(NH4)2SO4 molecular mass = (14+4) *2+32+4*16 =124g
10 g of (NH4)2SO4 correspond to 10/124 =0.0806mole
and as there are 4 moles of oxygen atom for 1 mole of product
so 0.0806*4 = 0.323 mole of oxygen atom
2007-02-17 21:13:38 · answer #1 · answered by maussy 7 · 0⤊ 0⤋
The number of moles of NH4SO4 is 10g divided by the molecular weight, which I'll leave you to calculate. A molecule of oxygen has two atoms. There are four oxygen atoms in NH4SO4 so it's twice the number of moles of NH4SO4.
2007-02-18 05:04:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
10/132 x 4
2007-02-18 05:01:23 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋
I'm gonna get some "thumbs down" ratings for this, but....
You kids need to do your own homework.
2007-02-18 05:01:28 · answer #4 · answered by Koosher 5 · 0⤊ 0⤋
200 may be
2007-02-18 05:06:06 · answer #5 · answered by boxer 3 · 0⤊ 0⤋