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i am using javascipt and php5....and want to test ajax...but i am not getting the required result( or lets say ajax is not working at all)..
javascipt is ok( i have seen al javascript console)....my php is running(i am using it with mysql to connect to database)..only ajax is not working...i am using just a simple program to run ( i am using dreamweaver to write the text)....do i need extra plug in to run ajax or what is the problem....(i am novice in ajax).
help me....

thanking in advance
abin awale

2007-02-17 20:35:52 · 3 answers · asked by abinawale 2 in Computers & Internet Programming & Design

3 answers

d'oh your ajax code is broken... or the xml isn't valid xml or you have security problems.....


that's all I can do without an URL or a mind meld.

2007-02-18 05:31:24 · answer #1 · answered by jake cigar™ is retired 7 · 1 0

If it have been caught in a loop, the website would seem to "dangle"... There are a number of subject concerns with your code. First: you probably did no longer declare a Doctype. 2d: you utilize a table for format. table DOM is notoriously confusing to handle - with the exception of the reality that tables are not meant for format. third: you're inconsistent with your code. a appropriate HTML ingredient makes use of double fees for attributes - you utilize a mix of single fees, double fees, and -worse- NO fees. Fourth: while using the "this.-" identifier, ensure the container has an identity assigned. 5th: do no longer use the anchor area of purely call a function. that's deprecated. quite, use the onclick/onmouseover experience in a span. SO: class 16d5cb38b21c4c951b717a2dd45e9d5 quite of the extraordinary now, the website certainly does an inner refresh through fact the link *works*. enormously while which contain JavaScript, appropriate coding will make issues plenty much less confusing to troubleshoot.

2016-10-15 22:21:43 · answer #2 · answered by Anonymous · 0 0

Provide your code here.

2007-02-19 21:21:58 · answer #3 · answered by Atif Majid 3 · 0 0

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