What is the weight of the Hubble telescpe at an orbt of radius 6.98X10^6 m as measured from earth's centre?
plz help?
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G= 6.67X10^-11Nm^2/Kg^2
r=6.38X10^6 m
2007-02-17 13:01:03 · 3 answers · asked by no name 1 in Science & Mathematics ➔ Physics
it is 12000 kg on earths surface
2007-02-17 13:38:10 · update #1
Ah now that you provided the mass the question in answerable.
To find the weight of the object at this distance from the earth you need to know what gravity's acceleration is at this point which you can find with this equation.
a=G*me/r where me is the mass of the earth, G is the gravitational constant and r is the orbital distance.
You take this number and multiply it by the mass of the satellite to find it's weight. Hope this is what you were looking for.
2007-02-17 14:15:07 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Things in orbit don't have weight; they are weightless, so the answer is it weighs zero. If the question means something else, then you don't have enough information. You at least would need the mass of the telescope for example.
2007-02-17 21:27:46 · answer #2 · answered by campbelp2002 7 · 0⤊ 0⤋
You would also need to know the orbital velocity to determine it's mass. . .
Addition:
Well, it's mass would not change, but it's weight, like the answer above stated, would be zero.
All object in ornit have 0 weight.
2007-02-17 21:39:33 · answer #3 · answered by Walking Man 6 · 0⤊ 0⤋