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2007-02-17 11:04:22 · 5 answers · asked by Sujashni J 1 in Science & Mathematics Other - Science

5 answers

2x-3y+6=0

2x+6 = 3y

y = (2x + 6)/3

y = 2x/3 + 2

__________________

x ___ y = f(x)

0 ___ 2
1 ___ 2.666
2 ___ 3.333
3 ___ 4
4 ___ 4.666
5 ___ 5.333
6 ___ 6
7 ___ 6.666
8 ___ 7.333
9 ___ 8

... etc

2007-02-17 11:10:23 · answer #1 · answered by Anonymous · 1 0

As you can see, the equation is very nearly in standard form for a linear equation. This makes it extremely simple to graph, even more so than when the equation is in slope-intercept form.

The first thing to do is change it to standard form, Ax + By = C. You can do this by subtracting 6 from both sides of the equation to get:

2x - 3y = -6

Since this is a linear equation, all you need is two points to graph the whole thing.

The easiest two points to use are the x-intercept and y-intercept.

To find those two points, plug in 0 for one of the variables and solve for the other variable. This finds the x value when the y value is zero, and the y value when the x value is zero.

In this particular example:

2(0) - 3y = -6
-3y = -6
y = 3, when x = 0

2x - 3(0) = -6
2x = -6
x = -3, when y = 0

Now you have the two intercepts, you can easily graph the rest of the equation by connecting the two points.

2007-02-17 19:19:59 · answer #2 · answered by ? 3 · 0 0

This can be tranfered to:
2x-3y=-6
-3y=(-6-2x)
y=(-2x-6)/-3
y=2/3x+2
Type this into your graphing calculator, or add in x values to solve for y.

2007-02-17 19:10:21 · answer #3 · answered by Evil Genius 3 · 0 0

·y=(2*x+6)/3
····················5.83┼
························│·········.¨°
························│······.¨°
························│···.¨°
························│.¨°
······················.¨°
···················.¨°··│
┼───────────────.¨°─────┼───────────┼
-10.0········.¨°········│·······5.00
··········.¨°···········│
·······.¨°··············│
····.¨°·················│
·.¨°····················│
°·······················│
····················-5.83

Copy and paste to a notepad

2007-02-17 19:30:55 · answer #4 · answered by runlolarun 4 · 1 0

Okay. done. what do i do next?

2007-02-17 19:07:13 · answer #5 · answered by Anonymous · 0 2

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