PHYSICS HELP please :)?

Question

Don't tell me the answer!!! i want to figure it out on my own.
but i need someone to explain/walk me through the steps.
here is the problem:

A person skis down a hill, accelerating at a constant 2.00m/s/s. If it takes her 15.0s to reach the bottom, what is the legnth of the slope?

which equation would i use:

1) Vf= Vi + аΔt

2) a= (Vf-Vi) / Δt

3) Δx = ViΔt + 1/2a(Δt)

Answer 1

use the fomula
x= 1/2at^2

good luck!

the third one.
they gave you time and acceleration.
there is time and accleration in the third. Because the object stars from rest, you don't need Vi*t

and by the way, you forgot to square the time.
it should be: Δx = ViΔt + 1/2a(Δt)^2

Answer 2

My physics is a bit rusty, but I believe that:

distance = velocity (0) * t + 1/2 (acceleration) (t)**2

Since the velocity (0) is 0, then distance = 1/2 (acceleration)x(t)**2

Answer 3

It looks like someone already helped but you should write m/s*s instead of m/s/s because that would be a stupid thing to get dinged for on a test.