2 in/ sec
15 ft/ min
4 yd/ min
2007-02-17 07:03:37 · 5 answers · asked by jrrkidd 1 in Science & Mathematics ➔ Mathematics
2 in/sec - slowest
4 yd/min - Middle = 2.4 in/sec
15 ft/min - fastest = 3 in/sec
2007-02-17 07:11:47 · answer #1 · answered by Anonymous · 3⤊ 0⤋
Use the well known connections between yards, feet and inches and between minutes and seconds to turn them all into in/sec. So 4 yd/min = 12 ft/min = 12 ft/ 60 sec etc. That's done enough for you.
2007-02-17 15:11:54 · answer #2 · answered by mathsmanretired 7 · 0⤊ 0⤋
2 in/ sec = 120 inches/min = 10 feet per min [slowest]
15 ft/ min = 15 feet / min [fastest]
4 yd/ min = 12 feet min [ in the middle]
2007-02-17 15:12:21 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
1. 15 ft per min
2. 4 yd per min
3. 2 in per sec
2007-02-17 15:27:07 · answer #4 · answered by just the facts 5 · 0⤊ 0⤋
I'll help you out, 4yd/min = 12ft/min and 2in/sec=120in/min=10ft/min
so:
2in/sec
4yd/min
15ft/min
2007-02-17 15:10:27 · answer #5 · answered by Nate R 2 · 0⤊ 0⤋