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2007-02-17 05:36:14 · 4 answers · asked by Sujashni J 1 in Science & Mathematics Mathematics

4 answers

Solve/isolate "x"...... 2(x-2) - (2x-7) < - 11

First: distribute the outer term with the terms in parenthesis.....

2(x) + 2(-2) - (2x-7) < - 11

2x + (- 4) - (2x-7) < - 11

2x - 4 - (2x-7) < - 11

*Disitrubte the outer negative sign with the terms in parenthesis....

2x - 4 - 2x - (-7) < - 11

2x - 4 - 2x + 7 < - 11

2x - 2x - 4 + 7 < - 11

- 3 < - 11

False

There is no solution.

2007-02-17 06:02:58 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0 1

shelter the inequality sign as though it have been an equivalent sign. thirteen.) 5x>2x+9 combine like words -2x -2x 3x>9 divide via 14.) -3x+3>9 combine like words -3x>6 divide via x>-2 with a damaging answer, replace the inequality sign around. 15.) 4x-5>2x+3 combine like words 2x>8 divide via

2016-12-17 12:18:23 · answer #2 · answered by Anonymous · 0 0

no solution x will never be less than -11 bcecause the x's cancel out 2x-2x=0 when u distribute

2007-02-17 05:42:34 · answer #3 · answered by Anonymous · 0 1

2(x - 2) - (2x - 7) < - 11

2x - 4 - 2x + 7 < - 11

3 < - 11

No solution

- - - - - - - - - s-

2007-02-17 06:27:59 · answer #4 · answered by SAMUEL D 7 · 0 0

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