Physics Equation help!?

Question

Look at the two equations:

Position [m] = A [m s-2] time^2 + b [m s-1] time + C [m]

y = y (sub 0) + v (sub 0) + 1/2 a t^2

What does the A stand for in the first equation??

a) initial velocity
b) current position
c) 1/2 acceleration
d) currect velocity
e) initial velocity

please help! thanks

Answer 1

Where did these equations come from? Pretty cryptic.

It's no wonder you are confused. The second equation is inaccurate - it is missing a time factor on the velocity term.

The two equations are, I believe, supposed to be the same.

y = final position = Position
y(sub 0) = initial position = C
v(sub 0) = initial velocity (speed) = b
t = time
a = acceleration = 2A

You should be able to figure out the answer to your question from there.

Answer 2

it's the half of the acceleration, c) answer,,, but you have a little mistake in the second equation, the second term (initial speed) has to be mulitplied by t (time) in order to keep consistency in the units...

Answer 3

The answer is c)

Note A is coefficient of t² in the upper eq., and ½ a plays the same role in the second. Therefore...