2007-02-17 04:21:11 · 22 answers · asked by Pickle Stench 1 in Society & Culture ➔ Cultures & Groups ➔ Lesbian, Gay, Bisexual, and Transgender
Why are you openly straight?
2007-02-17 04:24:24 · answer #1 · answered by Annie 5 · 1⤊ 1⤋
the main appropriate words selection by ability of project and individual companion is the politically maximum appropriate term. yet while they have had a dedication ceremony that's okay to call him husband. If no longer, it is likewise okay to bypass with boyfriend. it truthfully relies upon on what you're delicate with. to proceed to be expert i'd attempt and follow his first call, yet once you're able to introduce him or deliver it up your self only bypass look into his hand, and if there's a ring bypass with husband, if their isnt, companion is greater expert.
2016-11-23 15:03:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Your boss in openly gay b/c he/she is not ashamed of their lifestyle... are you openly straight? Think about it... seriously!
2007-02-17 04:24:01 · answer #3 · answered by Anonymous · 2⤊ 1⤋
Because that's his right as a naturally born gay man.
2007-02-17 04:43:07 · answer #4 · answered by Anonymous · 2⤊ 0⤋
well because hes gay and not embaresed by it theres nothing rong with being gay thats just who he is and hes proud of it
2007-02-21 02:43:51 · answer #5 · answered by emily 1 · 0⤊ 0⤋
You obviously have an issue about it. Why not discuss the subject with him. Or isn't your bigotry worth your job?
2007-02-17 05:01:10 · answer #6 · answered by castle h 6 · 0⤊ 0⤋
because they are happy with who they are and love themselves, if you can't handle working for someone that is gay, quite and be all that much poorer for it as a human being.
2007-02-17 04:45:30 · answer #7 · answered by Anonymous · 2⤊ 0⤋
It was the requirement for filling the position.
2007-02-17 04:31:31 · answer #8 · answered by Grist 6 · 0⤊ 0⤋
Cuz its a free world
2007-02-17 04:24:58 · answer #9 · answered by Anonymous · 2⤊ 0⤋
Because tolerance rules!
2007-02-17 04:26:27 · answer #10 · answered by Chipper 3 · 3⤊ 0⤋