154 grams of antifreeze absorbs 5045 joules of energy in going from 21.0°C to 350°C.what is the specific heat

Question

of the antifreeze?

a. 4.18J/g°C
b. 0.936J/g°C
c. 2.34J/g°C
d. 1.56J/g°C

Answer 1

use the formula

E = c*m*(change in temperature)

so your E is your joules
your m is your mass (154)
and your change in temperature is (350-21)

then solve for "c" and that will be your specific heat!

Answer 2

I'm assuming you mean 35.0 C, not 350, otherwise none of the answers is correct.

heat = specific heat * mass * temperature change
specific heat = 5045/(154*14) = 2.34 J/g C