(-32)^/3/5?

Answer 1

I'm assuming you meant (-32)^(3/5).

First, notice that -32 is the same as -2*-2*-2*-2*-2

x^(3/5) means the same as take the 5th root of x, and then raise that to the third power (or (x^(1/5))^3).

So (-32)^(3/5) = ((-32)^(1/5))^3 = (-2)^3 = -8

Answer 2

-32 times -32 times 3 times 5

Answer 3

First take the 5th root of (-32).
This is the number when multipled by itself 5 times will give - 32.
This is ( - 2)
Problem can then be set down as:-
(-32)^3/5 = (-2) ³ = - 8

Answer 4

If the question is:

(-32)^(3/5)

-32 = -2^5
(-2^5)^(3/5) = (-2)^3 = -8

Answer 5

The answer (to what you meant to type?) is (-32)^/3/5 = - 8.

This relies upon two basic kinds of fact:

A.) (-1)^(odd #) = -1, so (-1)^[1/(odd #)] = - 1. So also :

(-1)^[(odd #1)/(odd #2)] = - 1.

B.) 32 = 2^5.

Applying these facts:

(- 32)^(3/5) = (-1)^(3/5) (2^5)^(3/5) = - (2^3) = - 8. QED

Live long and prosper.

Answer 6

I suppose that you say: base -32, exponent 3/5
= root of 5\/-32³
rt ^5\/-2^5³
Cancelling exponents 5, remainder -2³ = -8
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Answer 7

(-32)^(3/5)

^(5)√-32³

(-32³)^(1/5)

((-2^5)³)^(1/5)

(-2^15)^(1/5)

-2³

-8