k someone help me with this plzzz its math help and hw?

Question

yolanda and yoko ran in a 100yd dash. When yolanda crossed the finish line yoko was r10yd behind her. the girls then repeated the race with yolanda starting 10yd behind the starting line.if each girl ran at the same rate as before who won the race? by how man yards?



question #2 ? Assuming the girls run at the same rate as before how far behind the starting line should yolanda be in order for the two to finish in a tie?

SOMEONE PLZZZZZ HELP ME

Answer 1

Since Yoko had only covered 90% of the distance, we can assume she runs at 90% of Yolanda's speed.
(Assuming they both run at constant speed. Of course in real life you don't but this is maths so never mind!)

You can solve this by picking an arbitrary number for the speed. Pick one that makes the numbers easy!

So, let's say Yolanda runs at 10 yards per second, so it took her 10 secs to run the first race.
This means poor fat Yoko runs at 9 yards per sec.

In the second race, Yolanda has to run 110 yards, so it takes her 11 secs.
In that 11 Secs, Yoko can only run 99 yards, so she finishes her 100 yards after Yolanda, ie she loses! When Yolanda is at the finish line, Yoko is 1 yard behind.


For the second question, we need to get Yoko and Yolanda finishing together, so we need Yoko to run 90% of Yolanda's distance. Yoko still has to do 100 yards, so
90% of Yolanda's distance = 100 yards

90% = 100yds
10% = 100/9 =11.1recurring yds
100% = ans x 10 = 111.1 recurring yds

So Yolanda has to start 11.1recurring yards behind Yoko.

(You will notice we bnever used our made-up speed for the second part of the question, just percentages. So it is true whatever speed they actually run at.)

Hope you got that!!!

Answer 2

question 1:
After Yolandra had run 100yd, she would have ran 90yd from the starting line, and has 10yds left. Yoko would have ran 90yd, and therefore being the same position as Yolandra. Because Yolandra is 10yd faster than Yoko in 100yd, she should be 1yd faster than Yoko in 10yd. Therefore, Yolandra won by a yard.

question2:
Yolandra ran 100yd in x seconds. Yoko ran 90yd in x seconds, which means, Yolandra is 10/9 times faster than Yoko. In any given amount of time, Yolandra will cover 10/9 times more distance than Yoko. Therefore, by the time Yuku ran 100yd, Yolandra would've run 100(10/9) which is approximately 111.1yds. Therefore, Yolandra has to start 11.1yds behind the starting line.

Answer 3

let the time taken by yolanda and yoko in the race to travel 100yds and 90 yds respectiveley be ' t'
so yolanda's speed = 100/t
yoko's speed will be = 90/t
now yolanda has to travel 110 yd s so time taken = 110t/100
= 1.10 t
time taken by yoko to travel a 100 yds = 100t/90
= 1.11t
so again the winner is yolonda.
distance travelled by yolanda = 110 yds
similarly distance travelled by yoko in time 1.10 t time = 99yds
so the distance between them = 100 - 99 = 1yd
now in order to finish at the same time
time taken be yoko to finish the 100 yd distance should be the distance covered by yolanda in the same time
in 10/9 t yolanda will cover the distance = 100/t * 10t/9
=1000/9yd
= 111.11yd
so yolanda should be standing 11.11yds before the start line
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Answer 4

yoko runs at 9/10 th the speed of yolanda. Lets say Yolanda runs at 10 secs. per yard( slow I know but the numbers still work out) so if you divide that by 9/10 you come up with a speed of 11.11 sec.per yard for yoko. So if yolanda runs 110 yards she finishes in 1100 secs. and if yoko runs 100 yards she finishes in 1111.11 secs. Yolanda still wins by 11.11 sec which is a 1 yard difference. To make up the time difference to be equal at the fiinsh line Yolanda must start 11.1 yards behind yoko.
111.1 yds.*10 sec. per yd.=1111 for yolanda
100 yds. *11.11 sec. per yd.=1111 for yoko

Answer 5

V = d/t

since you were not given time (t) try to make time cancel out.

Get the ratio of the fast girl's speed vs. the slow girl's speed,

V(yolanda) / V(yoko) = d(yol)/t(yol) divided by d(yok)/t(yok)
= 100/t(yol) divided by 90/t(yok)
You know that time is the same for both, because the problem says, at the moment yolanda crosses...
so, if you cancel out t, you get V(yol)/V(yok) = 1.11111. Now you know that yolanda is 1.11111 times faster than Yoko.
Also, for a given amount of time, Yolanda goes 1.11111 times farther in distance.
So, if Yolanda has to run 110 yards, Yoko ran 110/1.1111 = 99 yards in that amount of time. Yolanda reached the finish line, but Yoko was 1 yard short of the finish line. Yolanda won the race, by one yard.
Question 2.
Using the same ratio V(yol)/V(yok) and the times cancel out, you get d(yol)/d(yok) = 1.11111
You konw that yolonda is faster, so use d(yok) as 100 yards.
d(yol)/d(yok) = 1.11111
d(yol)/100 = 1.11111
so d(yol) = 1.11111 x 100 = 111 yards.
this is the total distance she has to run, so she has to be put 11 yards behind the starting line.
They will now run to finish a tie.

Answer 6

yoko lose by 20 yd