Calculate Kp for the reaction
NO(g) + O3(g) → NO2(g) + O2(g)
under the following conditions:
T = 298 K
Pressure of NO = 2.02 x 10-5 atm
Pressure of O3 = 1.20 x 10-5 atm
Pressure of NO2 = 2.80 x 10-6 atm
Pressure of O2 = 2.25 x 10-2 atm
Enter a numeric answer only
2007-02-17 02:16:31 · 3 answers · asked by Djuna 2 in Science & Mathematics ➔ Chemistry
Kp=[NO2][O2]/([NO][O3]
kp=[2.80*10^-5*2.25*10^-2]/ [2.02*10^-5*1.20*10^-5]
kp= 259.9=260.
good luck
2007-02-17 03:02:57 · answer #1 · answered by jennifer 2 · 1⤊ 0⤋
[(2.8*10^-6)(2.25*10^-2)]/[(2.02*10^-5)(1.20*10^-5)]
259.9 (no units, dimensionless)
2007-02-17 02:22:55 · answer #2 · answered by SS4 7 · 0⤊ 0⤋
Use this formula:- Kp=p(NO2)p(O2)/p(NO)pO3
2007-02-17 02:22:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋