2007-02-17 01:26:04 · 5 answers · asked by Starmu 1 in Science & Mathematics ➔ Physics
The object will still weigh the same.
If you weigh it with the string, the portion of string that is hanging down will have no measurable weight ,
But once a portion of the string rests on the scale then that portion will become weigh-able
2007-02-17 01:33:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋
weight = mass x g (gravitational pull)
As far as the object is concern, the string has no contribution to both
2007-02-17 01:34:38 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Weight is not dependent but period of oscillation depends on the length of the string.
2007-02-17 01:32:27 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
you haven't specified what u exactly want.
if the string has low Young's mod value it will break. otherwise the heavier weight will stretch the string with very infinitesimally
2007-02-17 01:43:34 · answer #4 · answered by shri 1 · 0⤊ 0⤋
Only in that a longer string is heavier. Aside from that there will be no effect whatsoever.
2007-02-17 01:30:55 · answer #5 · answered by poorcocoboiboi 6 · 0⤊ 0⤋