differentiate with respect to x:Question is: y=(u)power2-1/(u)power2+1 and u=[(x)power2+2]cube root?

Answer 1

dy/du=2u-2/(u^3)
u=3√(x^2+2)
du/dx= -2x/3(x^2+2)^(2/3)
dy/du*du/dx=[2u-2/(u^3)] x [-2x/3(x^2+2)^2/3]
dy/dx = [(2[(x)power2+2]cube root)-2/(x^2+2)] x [-2x/3(x^2+2)^2/3]