In Madras , temperature at noon varies according to t^2/2 + 4t + 12 (Read is as: t square /2 + 4t +12), where t is elapsed time. Find how much percentage of temperature is increased (or decreased) between 5pm and 8pm.
Can anyone please tell how to solve it, i need a method to solve it so pls dont provide only the answer, please help me...
2007-02-16 21:17:24 · 4 answers · asked by Kiran 2 in Science & Mathematics ➔ Mathematics
T = t² / 2 + 4t + 12
T5 = 25/2 + 20 + 12 = 44.5
T8 = 64/2 + 32 + 12 = 76
Increase = 31.5
% increase = 31.5 / 44.5 x 100 % = 70.8 %
2007-02-16 21:44:18 · answer #1 · answered by Como 7 · 0⤊ 0⤋
integrate the function from the limit t = 0 (5 pm) to t = 3 ( 8pm) ( if the unit of t in the function is 'hour'). This will give you the total increase in temperature. Find the temperature at 5pm by putting t = 0 in the given function. This will give you the initial temperature. From these 2 values you should be able to calculate percentage increase in temperature.
2007-02-17 05:29:47 · answer #2 · answered by rhapsody 4 · 0⤊ 0⤋
Unfortunately, you made a typo. "Temperature at noon" makes no sense when you're talking about later times.
So it's not clear what that function measures.
If you're looking for the percentage change in its value -- well, that's easy. If you're looking for something else, you may want to state the problem more clearly. The fact that you have t^2/2 in there suggests that you're probably in a calculus class and you're supposed to integrate the function, but if that's the case you REALLY need to state the problem more precisely.
2007-02-17 05:49:59 · answer #3 · answered by Curt Monash 7 · 0⤊ 0⤋
Rise or fall 28.5 degrees
2007-02-17 11:55:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋