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A hammer action (in a horizontal plane) acts as a propulsion force to a turntable.

The hammer weighing 1Kg depresses a push rod through 1 cms in 0.144 secs, which in turn is attached to a gear “A”. Gear A has a 1” radius and the push rod is attached to gear A at a radius of 0.9”. Gear A is mounted on the same shaft as gear “B” which has a 0.5” radius that in turn engages another gear “C”, which has a 3.5” radius attached to a turntable. (Assume a frictionless environment.)

Questions:
How much work does the hammer do per impulse?
What force is exerted on the push rod?
What force is exerted on gear C?

Many thanks

2007-02-16 20:28:46 · 2 answers · asked by Willy 1 in Science & Mathematics Physics

2 answers

Assuming a frictionless environment, if the hammer weighing 1Kg depresses a push rod through 1 cms in 0.144 secs, which in turn is attached to a gear “A”. Gear A has a 1” radius and the push rod is attached to gear A at a radius of 0.9”. Gear A is mounted on the same shaft as gear “B” which has a 0.5” radius that in turn engages another gear “C”, which has a 3.5” radius attached to a turntable.

2007-02-24 19:06:27 · answer #1 · answered by Esse Est Percipi 4 · 0 0

Consider linear and rotational momentums
also
Force and torque equation as a system.

I'll look at it tomorrow.

2007-02-22 23:53:51 · answer #2 · answered by Edward 7 · 0 1

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