Can u help me out in a maths problem?

Question

The vertices of triangle ABC are A(2,-11),B(2,13) ,C(-12,1).Find the equation of AB.

Answer 1

use the formula (x-x1)/(x1-x2)= (y-y1)/(y1-y2)

(x-2)/ (2-2)= (y+11)/(-11-13)

(x-2)/0 = (y+11)/ (-24)

-24(x-2) = 0

-24x + 48 = 0

x=2

Answer 2

x=2

Answer 3

AB is a line 24 units long running straigt up and down at x=2 from y= -11 to 13.

So the equation is x=2, -11 >y>13

Answer 4

The equation o a straight line passing through two points (x1,y1) and (x2,y2) is given by (y-y1)/(x-x1)=(y1-y2)/(x1-x2).

Here, A (x1,y1) is (2,-11) and B (x2,y2) is (2,13).

Hence the equation of the line passing through A & B is
(y+11)/(x-2)=(-11-13)/(2-2),
i.e. (x-2)/(y+11)=(2-2)/(-11-13)
i.e. x-2=0
i.e. x=2

You can find this out by observation, too. Notice the the x co-ordinates of both A & B are the same, i.e. 2. Hence the equation of the line thriughA & B must be x=2.

The co-ordinates of C are irrelevant here.

Answer 5

the equation of line AB need only two points A and B
y+11 = (13+11)/(2-2) {x-2}

as denometer is zero, so u have to cross multiply and we get:
x-2 = 0
so, equation of line is x=2, which is parallel to y axis at a distance of 2 units from Origin.

Answer 6

Plot the points A and B and join them to give line AB.
It will be seen that every point on the line is at distance 2 from the y axis.
This gives the equation of the line as x = 2

Answer 7

14

Answer 8

A= (2,-1)
B=(2,13)

M=Y2-Y1/X2-X1
=13-(-11)/2-2
=0

SO NOW THE FORMULA IS

Y-Y1=M(X-X1)
Y-(-11)=0
Y+12=0

SO THE ANSWER
IS

Y+12=0

Answer 9

2 ; get a pen and paper and try to draw the triangle, it is easy then after

Answer 10

use the distance and section formula to solve this problem