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WHAT IS DOMAIN DEFINITION OF FUNCTION?

2007-02-16 19:35:49 · 7 answers · asked by hitmast3r 1 in Science & Mathematics Mathematics

7 answers

f(x) = x/(x+1)

if x --> +infinity, f(x) --> 1 (f(x)<1)
if x --> -1 (x > -1) , f(x) --> -infinity
if x --> -1 (x< - 1), f(x) --> + infintiy
if x --> -infinity, f(x) --> 1 (f(x)>1)

domain x is: x <> -1
domain f(x) is: f(x) <> 1

2007-02-16 19:40:53 · answer #1 · answered by seah 7 · 1 0

The domain is the set of numbers which, when substituted into the function, allow a valid solution

In this case, any number is valid except -1 (as that would lead to division by 0) so the domain is (-∞,-1)U(-1,∞)

2007-02-17 03:41:12 · answer #2 · answered by Tom :: Athier than Thou 6 · 0 0

The domain is the set of all possible real numbers x such that the equation yields a real answer for f(x).

In this case, any real number x will yield a real answer for f(x) except -1. Why -1? Because -1/(-1+1) = -1/0. It is undefined, and not a real number.

2007-02-17 03:39:13 · answer #3 · answered by Karinissima 5 · 1 0

Domain: x is all real numbers except for -1
This is because when -1 is put in for x, the denominator comes out to be 0, and that is undefined. Any other number would work and become a fraction.

2007-02-17 03:39:49 · answer #4 · answered by pianist929 3 · 0 0

f(x) is not defined when x = -1 because division by zero is not possible.

The domain of f(x) is therefore all Real numbers with the exception of x.

This could be shown as {R - 0}

2007-02-17 07:08:25 · answer #5 · answered by Como 7 · 0 0

All real numbers except x=-1

2007-02-17 15:35:59 · answer #6 · answered by santmann2002 7 · 0 0

all real except -1

2007-02-17 03:41:49 · answer #7 · answered by holdencaufield 2 · 0 0

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