f(x) = x/(x+1)
if x --> +infinity, f(x) --> 1 (f(x)<1)
if x --> -1 (x > -1) , f(x) --> -infinity
if x --> -1 (x< - 1), f(x) --> + infintiy
if x --> -infinity, f(x) --> 1 (f(x)>1)
domain x is: x <> -1
domain f(x) is: f(x) <> 1
2007-02-16 19:40:53
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answer #1
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answered by seah 7
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The domain is the set of numbers which, when substituted into the function, allow a valid solution
In this case, any number is valid except -1 (as that would lead to division by 0) so the domain is (-â,-1)U(-1,â)
2007-02-17 03:41:12
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answer #2
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answered by Tom :: Athier than Thou 6
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The domain is the set of all possible real numbers x such that the equation yields a real answer for f(x).
In this case, any real number x will yield a real answer for f(x) except -1. Why -1? Because -1/(-1+1) = -1/0. It is undefined, and not a real number.
2007-02-17 03:39:13
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answer #3
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answered by Karinissima 5
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Domain: x is all real numbers except for -1
This is because when -1 is put in for x, the denominator comes out to be 0, and that is undefined. Any other number would work and become a fraction.
2007-02-17 03:39:49
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answer #4
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answered by pianist929 3
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f(x) is not defined when x = -1 because division by zero is not possible.
The domain of f(x) is therefore all Real numbers with the exception of x.
This could be shown as {R - 0}
2007-02-17 07:08:25
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answer #5
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answered by Como 7
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All real numbers except x=-1
2007-02-17 15:35:59
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answer #6
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answered by santmann2002 7
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all real except -1
2007-02-17 03:41:49
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answer #7
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answered by holdencaufield 2
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