I need help with Hardy-Weinberg question?

Question

The question is:

In a population it was reported that the allele frequency for M was 80% and for N was 20% in the MN blood group system. M and N are CO-DOMINANT alleles. In your words, describe the steps used to determine blood group frequencies.

If I knew how to do this, I would use my own words....Please help if you can?

Answer 1

In Hardy-Weinberg:

p = the frequency of one allele (let's say M) = 0.8
q = the frequency of the other allele (N) = 0.2

The frequency of MM individuals = p squared = 0.64
The frequency of MN individuals = 2pq = 2(0.8)(0.2) = 0.32
The frequency of NN individuals = q squared = 0.04

Answer 2

I'm not quite sure about the way you do it,but this is how i do it.

total number of M genes 80
" " N 20

M + N
80 + 20 =100

frequency of allele M is = 80 by 100 =0.8
" " N " = 20 by 100 =0.2

This is the best i can help.