English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

You sample a population of Salmonella typhimurium from a
popular local hamburger joint Howdyburger. You find 8 isolates
(clones) that are resistant to the antibiotics ampicillin and
kanamycin, 27 isolates that are resistant to amipicillin and
kanamycin, and 53 isolates that are susceptible to both
antibiotics. What is the frequency of each of the three types
in the Howdyburger population? What is the genetic
heterozygosity of the Howdyburger population?

I know that the frequencies are 1/11=.09, 27/88=.31, and 53/88=.6. But I don't really know what or how calculate the genetic heterozygosity?

2007-02-16 15:24:52 · 2 answers · asked by motobecane 2 in Science & Mathematics Biology

2 answers

I don't get it. How can a 1N bacteria exhibit any heterozygosity? Are these genes on plasmids? Both of the first two groups have the same phenotype, have you typed the question correctly?

My quick answer and initial impression is to say that the level of heterozygosity is 0, because you can't have heterozygosity in a haploid organism. You need to start talking about haplotypes then.

2007-02-17 03:20:31 · answer #1 · answered by floundering penguins 5 · 0 0

P^2 + 2pq + Q^2 = 1

2PQ= heterozygous.

2007-02-16 15:29:54 · answer #2 · answered by Anonymous · 0 0

fedest.com, questions and answers