Trick Question...?

Question

How long is a year on Earth?

Answer 1

Hi Everbody
now apparently Escort500 wasnt listening in class and is quite gullible because he said that every four years is a leap so lets add this up
1/4+1/4+1/4+1/4=4/4 Which means every Fifth year would be a leap year.
So an Earth Year is 365 days and a 1/3.
Just for Escort lets do the math again
1/3+1/3+1/3=3/3 which would mean that every fourth year is a leap year
Try using your other brain escort.

Answer 2

I wonder what and where you went to school. Or didn't/weren't you listen/ing? Maybe you were absent?
365 and 1/4 days. There is an adjustment there for that 1/4 day giving us a 'leap year', in February, (yes, that is spelled correctly) every four years.

Answer 3

From http://en.wikipedia.org/wiki/Year
* 353, 354 or 355 days — the lengths of common years in some lunisolar calendars

* 354.37 days — 12 lunar months; the average length of a year in lunar calendars

* 365 days — a common year in many solar calendars

* 365.24219 days — a mean tropical year near the year 2000

* 365.2424 days — a vernal equinox year.

* 365.2425 days — the average length of a year in the Gregorian calendar

* 365.25 days — the average length of a year in the Julian calendar

* 365.2564 days — a sidereal year

* 366 days — a leap year in many solar calendars

* 383, 384 or 385 days — the lengths of leap years in some lunisolar calendars

* 383.9 days — 13 lunar months; a leap year in some lunisolar calendars

An average Gregorian year is 365.2425 days = 52.1775 weeks, 8,765.82 hours = 525,949.2 minutes = 31,556,952 seconds (mean solar, not SI).

A common year is 365 days = 8,760 hours = 525,600 minutes = 31,536,000 seconds.

A leap year is 366 days = 8,784 hours = 527,040 minutes = 31,622,400 seconds.



However, if you want to relate a "year" to an orbital period, be warned, you have to decide which orbital period you want:
(from http://en.wikipedia.org/wiki/Orbital_period )

* The sidereal period is the time that it takes the object to make one full orbit around the Sun, relative to the stars. This is considered to be an object's true orbital period.

* The synodic period is the time that it takes for the object to reappear at the same point in the sky, relative to the Sun, as observed from Earth; i.e. returns to the same elongation. This is the time that elapses between two successive conjunctions with the Sun and is the object's Earth-apparent orbital period. The synodic period differs from the sidereal period since Earth itself revolves around the Sun.

* The draconitic period is the time that elapses between two passages of the object at its ascending node, the point of its orbit where it crosses the ecliptic from the southern to the northern hemisphere. It differs from the sidereal period because the object's line of nodes typically precesses or recesses slowly.

* The anomalistic period is the time that elapses between two passages of the object at its perihelion, the point of its closest approach to the Sun. It differs from the sidereal period because the object's semimajor axis typically precesses or recesses slowly.

* The tropical period, finally, is the time that elapses between two passages of the object at right ascension zero. It is slightly shorter than the sidereal period because the vernal point precesses.

Answer 4

365 1/4 days

Answer 5

a year on earth is the amount of time it takes for the earth to go around the sun and return to its starting point (one complete orbit)

Answer 6

365 days or 12 months, or approximately 114.25 weeks. A year on Earth is extremely long is all i really know...........

Answer 7

Lets see....365 days a year plus a leap day every four means 365.25 days and change....or so.

Answer 8

365 days, one revolution around the sun.

Answer 9

365 & 1/4 DAYS. :)

Answer 10

one rotation around the sun