Parallel Circuit?

Question

I have a circuit it resembles to rectangles. So there are 3 rows connected in parallel. The top row has a 1 ohm resistor. The second row (which is connected to row 1 and 3) has a 2 ohm resistor followed by a 1 volt battery (from left to right). The bottom row has a 3 ohm resistor followed by a volt battery (left to right). So there are 3 resistors and 2 batteries.

What is the magnitude of the current in the 2 ohm resistor?

I used the junction and loop rule and I came up with 1/3 amps on the top loop and 1 amp on the bottom loop, combined to get 1.33 Amps, but my professor says its wrong.

The bottom battery is 4 volts sorry

Answer 1

I can help you with ths problem, but I need to see a picture. Is there something you can draw out? Or post a picture?

Answer 2

current in top row I1
current in middle row I2
current in bottom row I3

voltage in top row V1 = R1*I1
voltage in middle row V2 = R2*I2 - U2
voltage in bottom row V3 = R3*I3 - U3

Now:
I1 + I2 + I3 = 0
V1 = V2 = V3,
so we have three simultaneous linear equations for three variables I1, I2, I3:

I1 + I2 + I3 = 0
R1*I1 = R2*I2 - U2
R1*I1 = R3*I3 - U3

or

I1 = -(U2 + U3) / (1 + R1/R2 + R1/R3)
I2 = 1/R2 (R1*I1 +U2)
I3 = 1/R3 (R1*I1 +U3)