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Batman, whose mass is 76.0 kg, is holding onto the free end of a 13.0 m rope, the other end of which is fixed to a tree limb above. He is able to get the rope in motion as only Batman knows how, eventually getting it to swing enough that he can reach a ledge when the rope makes a 58.0° angle with the vertical. How much work was done by the gravitational force on Batman in this maneuver?

2007-02-16 06:06:27 · 2 answers · asked by Victoroza 1 in Science & Mathematics Physics

2 answers

He rises 13- 13 cos 58 = 6.11m .So the work done is

W = m g h = 76*9.81*6.11=4556.15 joules

2007-02-16 06:22:01 · answer #1 · answered by santmann2002 7 · 0 0

10 N

2007-02-16 14:28:39 · answer #2 · answered by Anonymous · 0 1

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