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Need help solving a problem
A cat chases a mouse across a 1.3 m high
table. The mouse steps out of the way, and
the cat slides out of the table and strikes the floor
1.8 m from the edge of the table.
The acceleration of gravity is 9.81 m/s2 :
What was the cat's speed when it slid of
the table?

I dont think is possible for this problem to be done since I dont have the time it took for the cat to hit the floor. Can anybody help me if is possible

2007-02-16 05:08:37 · 2 answers · asked by theguy 2 in Science & Mathematics Physics

2 answers

A cat and a mouse problem Hmmm...
1. The horizontal speed remains the same, assuming no air resistance. S=vt v=? as you have suggested let's look for time t
2. The time t in takes the cat to hit the floor equal to the time t the cat falls from the table of height h.
h=.5gt^2
t=sqrt(2h/g)
S=v sqrt(2h/g)
v=S/sqrt(2h/g)
v=1.8/sqrt(2 x 1.3/9.81)=
v=3.5 m/s

2007-02-16 05:14:36 · answer #1 · answered by Edward 7 · 0 0

Let´s suppose that the cat has only horizontal velocity
The equations of the movement are

y= -9.81t^2/2 +1.3

x=Vo*t so t= x/Vo and when the cat srtikes the floor t=1.8/Vo

but at that time y=0 so

0= -9.81/2 *(1.8)^2 /Vo^2 +1.3 so 1.3*Vo^2 = 9.81/2*(1.8)^2
And Vo=3.5 m/s

2007-02-16 13:26:43 · answer #2 · answered by santmann2002 7 · 0 0

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