If you have yx-x=3y+2, how would you solve for x?
My book says you can divide by y-1, but why would that give you x on the left if it's yx-x, it's not yx-1??
2007-02-16 00:23:07 · 3 answers · asked by nicki s 1 in Science & Mathematics ➔ Mathematics
x(y-1)=(3y+2)
x=(3y+2)/(y-1)
2007-02-16 00:27:03 · answer #1 · answered by Maths Rocks 4 · 0⤊ 0⤋
On the left side of the equation you have xy-x, we can take x as a factor out so that x(y-1) = xy-x. Remember when you are doing multiplication of a term in brackets, you multiply the x by the first term in the bracket which is y, and then you multiply the x with the second term in the bracket -1. When factoring out is the same process in reverse.
x=(3y+2)/(y-1).
2007-02-16 08:33:03 · answer #2 · answered by The exclamation mark 6 · 0⤊ 0⤋
yx-x = 3y+2
x(y-1)=3y+2
divide by y-1 both sides
so x = (3y+2)/(y-1)
2007-02-16 08:36:03 · answer #3 · answered by falcon 1 · 0⤊ 0⤋