prove that 1>0?

Answer 1

If 0 < a and 0 < b, then 0 < a*b. THAT has to be part of the definition of < .

Either 1 > 0 or 1 < 0. (That follows directly from part of the definition too.)

In the latter case, 0 < -1.

Either way, 0 < 1*1 = (-1) * (-1) = 1.

Q.E.D.

Answer 2

Should be 0.

Answer 3

I believe the proof that 1 > 0 involves some fairly advanced set theory. The solution to this problem is the sort of thing that is taught at honours university level. And the proof for 1 + 1 = 2 is about 5 pages long. Sorry I can't be of more assistance.

Answer 4

To prove 1 > 0.
We know that 5 > 4
so subtract by "4" on both sides
we get
5 - 4 > 4 - 4
1 > 0
Hence proved.

Answer 5

assume that 0>1
subtract 1 from both sides
=> 0-1 > 1-1
=> -1 > 0
But we knw 0 is greater than negative
hense contradiction to what we assumed
so 0 < 1

(i just tried my math skills.....)

Answer 6

Well intelligent ques 2 ask !!! really u r one chap who got into depth of math!!! well of course d ans to dis ques doesn't lie in ny of ur txt buks!!! neither is it bcause 10>9 so we subtract 9 4m both side!!!! D ques ur askin doesn't come 4m theoritical mathematics but physical assumptions!!! like v assumed 2 denote a single distinguishable object by symbol '1'!!! nd moreover '0' was given 4 a null value so a single existing unit should b more in no. dan it !!!ny ways gr8 ques pal!!

Answer 7

that is same 0

Answer 8

i dont think there is any proof for that.. You may take that as an assumption or in math jargon a hypothesis..
If you do have a proof, pl post it here..

Answer 9

a>b <=>
exist u : strict positive number
and
b+u=a

in your case
a=1
b=0
u=1
:)