Determine the next term of the sequence 1,1,1,3,1,4,1,1,3,6,1,2,3,1,4, ?

Question

Find the next term of the sequence. (to be sure)
Determine the next term of the sequence 1,1,1,3,1,4,1,1,3,6,1,2,3,1,4, ?

Can anybody explain?

Answer 1

Answer to your question:
http://www.research.att.com/~njas/sequences/A055187

Answer 2

suitable if it starts off off with n=0 then (5^n+one million)/2 works (5^0+one million)/2=2/2=one million (5^one million+one million)/2=6/2=3 (5^2+one million)/2=26/2=thirteen as for the 2d sequence x(one million)=one million x(n+one million)=(x(n)+2)/5 everybody comprehend that each of x(n) is a fraction and according to possibility each and each so many times an integer so one can precise x(n) in terms of two sequences p(n) and q(n) such that x(n)=p(n)/q(n) p(n+one million)/q(n+one million)=x(n+one million)=( (p(n)/q(n))+2)/5= ((p(n)+2q(n))/q(n))/5= (p(n)+2q(n))/(5q(n)) subsequently p(n+one million)=p(n)+2q(n) and q(n+one million)=5q(n) its straightforward to artwork out that q(n)=5^(n-one million) subsequently p(n+one million)=p(n)+2*q(n) p(n+one million)=p(n)+2*5^(n-one million) now it is going to be straightforward to artwork out that p(n)=5^0+2*sum(5^t, t=one million to n-one million) sum(5^t,t=one million to n-one million) is a geometrical progression sum and is equivalent to (5^n-5)/4 so we've p(n)=one million+[(5^n-5)/2] p(n)=[5^n-3]/2 subsequently x(n)=p(n)/q(n) x(n)=[5^n-3]/[2*5^(n-one million)] x(n)=(5/2)-(3/2)*5^(one million-n) in case you have any questions be happy to email me and that i ought to be greater desirable appropriate than happy that would easily assist you further