can you solve this for me please?

Question

if y= (4x+3)^(5x+6)
what is y', if
Y' = y·[ 5*log(4*x+3) + (4*(5*x+6))/(4*x+3) ]

Answer 1

what is Y'???

what I would do is:
y= (4x+3)^(5x+6)
log y = (5x+6) log (4x+3)
now take the derivative using implicit differentiation:
y' /y = (5x+6)4/(4x+3) + 5 log(4x+3)
therefore
y' = y [ 4(5x+6)/(4x+3) + 5 log(4x+3)] therefore
y' = (4x+3)^(5x+6) [ 4(5x+6)/(4x+3) + 5 log(4x+3)] .

Answer 2

Y' inverse? Derivitive? can you be specific,
Mathematically you already know what y' is by what you have given

y' = y·[ 5*log(4*x+3) + (4*(5*x+6))/(4*x+3) ]
=(4x+3)^(5x+6)·[ 5*log(4*x+3) + (4*(5*x+6))/(4*x+3) ]

unless you know x you will not know y or y' as a value. What are the instructions? simplify logs? Solve? ..