Chemistry?

Question

1.) If 4.50 mol of silver nitrate reacts, what mass of sodium bromide is required?
b.) What mass of silver bromide is formed?

2.) If 2.25 g of silver are produced from the reaction, how many moles of copper(II) nitrate are also produced?

b.) How many moles of each reactant are required in this reaction?

Answer 1

1. 4.50 moles of silver nitrate would need 4.50 moles of sodium bromide to completely react, or 464 grams (MW NaBr = 103). You would potentially form 4.50 moles of silver bromide, or 846 grams (MW AgBr = 188).

2. I'm presuming you're talking about this reaction:

2 AgNO3 + Cu ---> 2 Ag + Cu(NO3)2

2.25 grams of silver is 0.0208 moles, so you would produce 0.0104 moles of copper nitrate. You would need 0.0208 moles of silver nitrate and 0.0104 moles of copper metal.

Answer 2

Don't you have chemistry books or a teacher that can answer this. Whats a mole anyway is it like a mule?