I need for someone to check my first problem and help me solve the second.
1. 7(e-f)-3(2e-3f)
....7e-7f-6e+9f
...........e+2f
2. The smaller of two consecutive integers is one less than half of the greater.
i was thinking it was like this...
x, x+1.......... x=x+1(over 2) -1
i hope the over 2 did not confuse you. i mean x+1 divided by 2
2007-02-15 13:54:53 · 3 answers · asked by austinblnd 4 in Education & Reference ➔ Homework Help
by the way, i have to find the equation for number 2, and simplify number 1.
2007-02-15 14:07:16 · update #1
1 is right and your equation for 2 is also right.
To solve it you would first add 1 to both sides since that's the inverse of -1, then multiply both sides of the equation by 2 since that's the inverse of dividing by 2.
This comes out 2(x + 1)= x + 1
2x + 2 = x + 1
Then move the terms with x to one side and the other terms to the other; you probably know what to do from here.
2007-02-15 13:59:42 · answer #1 · answered by hayharbr 7 · 0⤊ 0⤋
The first one looks great!
Try -1 and 0....
2007-02-15 22:02:46 · answer #2 · answered by Anonymous · 0⤊ 0⤋
the first one is right. the second one i think would be right, if you were supposed to write the equation.
2007-02-15 22:01:42 · answer #3 · answered by k 4 · 0⤊ 0⤋