In 1967, Green Bay beat Kansas City by 25 points in the first Super Bowl. If a total of 45 points were scored, what was the final score of the game? Write the equation to solve please.
2007-02-15 12:59:58 · 10 answers · asked by william74044 3 in Education & Reference ➔ Homework Help
Where x represents the number of points scored by Kansas City.
x + (x + 25) = 45
2007-02-15 13:02:58 · answer #1 · answered by Joy M 7 · 0⤊ 1⤋
Let x= Kansas City's score
Let (x+25)= Green Bay's score
x+(x+25)=45
2007-02-15 21:07:23 · answer #2 · answered by whitestblackwolf 1 · 0⤊ 1⤋
25+x=45
2007-02-15 21:19:36 · answer #3 · answered by Roots Above, Branches Below 3 · 0⤊ 0⤋
45-25=
2007-02-15 21:04:19 · answer #4 · answered by Najet K 2 · 0⤊ 1⤋
Kansas City = x
Green Bay = x + 25
x+x+25 = 45
Solve for x. 2x = 20, x = 10. Kansas 10, Green Bay 25. You're welcome.
2007-02-15 21:08:54 · answer #5 · answered by Anonymous · 0⤊ 1⤋
You know the answer so
= 45
You you know that GB - 25 = K
You know that K+GB = 45
Substitute GB -25 for K
(GB -25) + GB = 45
Combine like terms
2GB -25 = 45
Add 25 to both sides
2GB = 70
Divide both sides by 2
GB = 35
K = GB - 25, K= 10
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Check 10 + 35 = 45
2007-02-15 21:08:39 · answer #6 · answered by Ron H 6 · 0⤊ 1⤋
Scored by who, Kansas or green bay?
2007-02-15 21:03:44 · answer #7 · answered by aysha a 2 · 0⤊ 1⤋
x + (x+25) = 45
2x+25 = 45
2x=20
x=10
so the score is 10-35
2007-02-15 21:04:20 · answer #8 · answered by Shakespeare, William 4 · 1⤊ 1⤋
x = KC score
y = GB score
y = 25 + x
x + y = 45
x + 25 + x = 45
2x + 25 = 45
2007-02-15 21:04:02 · answer #9 · answered by Anonymous · 0⤊ 1⤋
25+x=45
45-25=20
x=20
2007-02-15 21:03:09 · answer #10 · answered by Sami F 3 · 0⤊ 1⤋