really complicated math problem any one out dere da could help!!?

Question

your teacher gies you the following directions: choose any intege. multiply it by negavite four. add ten. divide your answer by two. add triple your original number. subtract 12 from your answer. add negative 10. then add 32. your teacher then asks you for your final number. you reply 18, and the teacher says, your integer was 3, how did the teeacher know your original number??..........help!!! please!!!

i need to know how you figured that out....explain plszzzz

but what if your interger was 2? your answer would be 19....that rule doesnt work so its not right...rite?because if your answer is 19 (19 -15 = 4) so yea i has to work in all types of situations or types of numbers

Answer 1

why don't u do it your self jj

Answer 2

It's really just a simple algebra. First, substitute the unknown with any letter and form your working equation using the given operations: {(-4n + 10)/2} + 3n - 12 + (-10) + 32 = y; n is the unknown integer and y is the answer after doing the operations with the integer. You just simplify the equation to arrive at this:
-2n+5+3n+10=y then finally n=y-15. Given that you arrived at y=18, n can be simply solved. And that gives your original integer.

Answer 3

Because your original number is whatever number you answer back minus 15.

Write the whole thing out: let N=your original number,

Then the whole slew of operations you said you did on it comes out to this:

(-4N+10)/2 + 3N-12-10+32

Simplyfy that and you get the expression N+15. When the teacher asked you for the number you got, he just set it that to equal N+15. Subtract 15 out of it and he gets your original number.

Answer 4

The formula is A=15+I. next time do the math for your integer, then compare it to other integers to find the relationship and work out the formula.

Answer 5

Because your final result is always 15 more than what you began with.