2007-02-15 07:53:49 · 3 answers · asked by pattycake9000 1 in Science & Mathematics ➔ Physics
v = at
V = 80
t = 8
a = 10mph/sec^2
2007-02-15 07:58:28 · answer #1 · answered by John T 6 · 0⤊ 0⤋
60 mph = 88 ft/s [ ### -- see footnote], so v = 80 mph = (4/3) 88 ft/s.
But v = a t, so a = v / t = (4/3) 88 / 8 ft/s^2, that is
acceleration ' a ' = 44/3 ft/s^2 = 14.66... ft/s^2 [ *** -- see footnote.]
Live long and prosper.
### Footnotes:
1. This extremely convenient conversion information can be found in many State Drivers' Handbooks, in a section dealing with "stopping distances."
*** 2. 'John T's' answer, a = 10mph/sec^2, is NOT expressed in any units that you will find in standard references. And in fact, it's DIMENSIONALLY WRONG, because it has dimension L / T^3. The dimensions of acceleration are of course L / T^2.
2007-02-15 08:06:30 · answer #2 · answered by Dr Spock 6 · 1⤊ 0⤋
OMG i love that ride!
2007-02-15 08:00:21 · answer #3 · answered by bicker12 1 · 0⤊ 0⤋