refractive index of water is 4/3. what is the distance betwen the bird and fish?
2007-02-15 03:24:42 · 7 answers · asked by smrithi s 1 in Science & Mathematics ➔ Zoology
13 meters. The refractive index has nothing to do with the absolute distance
2007-02-15 03:29:10 · answer #1 · answered by frozen 5 · 1⤊ 1⤋
The distance meant here is definitely not absolute, but the distance of sight apparent for the fish, isn't it? ;)
Otherwise, the question is meaningless..
Let's consider equal distances are those passed by the light ray in a same time.
Given Vair is the velocity of light in the air,
Vwater is the velocity of light in the water.
As the refractory index of air is 1.0002926, let's assume Vair=c (speed of light in vacuum)
Then
c/Vwater = Nwater
Let equivalent distance in water is Dwater (i.e. the distance to be passed by light in vacuum~air within the time it travels the depth of the pond).
Then
Dwater = Depth*Nwater = Depth*4/3=4/3 m
Dtotal = Dair + Dwater = 13.333 m
2007-02-15 04:04:29 · answer #2 · answered by Eugene Ilyichev 1 · 0⤊ 1⤋
was this supposed to be a googly, my son (6 years) helped me add it up for you. It is 12+1 = 13m since you have cleared mentioned distances in absolute terms
2007-02-15 03:42:05 · answer #3 · answered by surnell 4 · 0⤊ 0⤋
is the fish is in the pond
2007-02-15 16:26:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋
13m
2007-02-16 02:16:19 · answer #5 · answered by saurabh.sable 2 · 0⤊ 0⤋
13m
2007-02-15 03:31:21 · answer #6 · answered by sarath v 1 · 0⤊ 0⤋
Frozen is right.
2007-02-15 03:33:08 · answer #7 · answered by Ricky J. 6 · 0⤊ 0⤋