The circle (x+2)2*+(y-5)2*=169 meets the positive coordinate axes at C(c,0)and D(0,d). (2* = squared)
a) Find the value of c and d
b) Find the area of triangle OCD,where Ois the origin.
2007-02-15 03:01:09 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a) To find c, substitute c,0 into the equation.
(c+2)2* + 25 = 169 ; c+2 = sqrt ( 144) = +/- 12; c=10 (question states c is positive so -14 is not a valid solution)
likewise for d
4+ (d-5)2* = 169; d-5 = sqrt (165) = +/- 12.85; d=17.85
b) Since OCD is a right angled triangle. A=1/2 * c * d = 99.25
Note, I think your question may be mistyped, should it read (x-12) ? c=24, d=10, A=120
2007-02-15 03:09:30 · answer #1 · answered by kinvadave 5 · 0⤊ 0⤋
in order to find out where the circle meets the x axis, plug 0 into the y value of the function, do the same for the D value, plug 0 into the x value and then solve.
once you've found those, all you have to do is use (1/2)CD in order to get the area of the triangle
2007-02-15 03:12:37 · answer #2 · answered by catatonic_sociopath 1 · 1⤊ 0⤋
What's this? University Challenge? I don't even know where to start.
2007-02-15 03:06:02 · answer #3 · answered by Misha-non-penguin 5 · 0⤊ 0⤋
c=150
d=160
area 1/2bd=12000
2007-02-15 03:09:33 · answer #4 · answered by Anonymous · 0⤊ 1⤋
I don't know the answer. Maybe you should try it yourself?
2007-02-15 03:04:01 · answer #5 · answered by risa_rific 3 · 0⤊ 0⤋
Not even when I'm sober.
2007-02-15 03:47:21 · answer #6 · answered by Anonymous · 0⤊ 0⤋