Just stuck on my A-level maths homework, need this to get started on an intergration by substitution.
2007-02-15 02:24:29 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
dx(sin4x)=4cos4x
this is because:
1) the derivative of sin[insert argument] is cos[insert argument]
2) the derivative of the argument 4x is 4
ergo, the derivative is 4cos4x
2007-02-15 02:28:58 · answer #1 · answered by millie 3 · 1⤊ 0⤋
4 cos 4x
2007-02-15 02:27:20 · answer #2 · answered by Alias 2 · 0⤊ 0⤋
f(x) = sin(4x)
f `(x) = 4 cos (4x)
Rule of thumb is to say:-
"differentiate sin(bracket)" to obtain cos(bracket)
ie cos(4x)
"differentiate bracket" to obtain 4
Now multiply these two results to obtain answer.
2007-02-15 02:54:42 · answer #3 · answered by Como 7 · 0⤊ 0⤋
d/dx(sin4x)=cos4x*d/dx(4x)
=4cos4x
2007-02-15 02:29:40 · answer #4 · answered by kushal 2 · 0⤊ 0⤋
Hi Alicia :-) Hope this helps...... ln (tan 2x) = 2.303*(log e (tan 2x)) therefore differentiate 2.303*(log e (tan 2x)) with respect to x i.e.(2.303)* {1 / (tan 2x)}*(2(sec 2x) (sec 2x) that equals 4.303(cosec 2x)(sec 2x)
2016-05-24 03:14:31 · answer #5 · answered by Penelope 4 · 0⤊ 0⤋
4cos4x
2007-02-15 03:05:14 · answer #6 · answered by JAMES 4 · 0⤊ 0⤋
4cos4x
2007-02-15 02:27:29 · answer #7 · answered by Michele C 2 · 0⤊ 0⤋
y=sin4x
let u=4x
du/dx=4
y=sinu
dy/du=cosu
dy/dx=dy/du*du/dx=cosu*4
=4cos4x
i hope that this helps
2007-02-15 06:27:31 · answer #8 · answered by Anonymous · 0⤊ 0⤋
using chain rule, d(sin(4x))/dx = cos(4x)•d(4x)/dx = 4cos(4x).
2007-02-15 02:31:18 · answer #9 · answered by Philo 7 · 1⤊ 0⤋
4cos4x
[(d(sin4x)/dx)(d(4x)/dx)]
2007-02-15 02:30:26 · answer #10 · answered by Maths Rocks 4 · 0⤊ 0⤋