what is the quadratic formula?

Answer 1

x={-b +or- (b^2-4ac)^2}/2a

Answer 2

The solutions to any quadratic equation ax^2 + bx + c = 0 are given by this formula:

X = - b +- √ b^2 - 4 ac
2a

Note square root is all over b^2 - 4*a
And all the top line divided by the bottom 2*a

Answer 3

the quadratic formula is used to solve the roots (normally two) of a equation of the form:

ax^2+bx+c=0 (equation 1)

This will yield

x= (-b+/- sqrt (b^2-4ac))/2a

Where +/- signifies + or -, sqrt is the square root, and a, b, c are the constants used in equation 1.

For one root, x1, the equation is

x1= (-b+ sqrt (b^2-4ac))/2a

For the other root, x2, the equation is

x2= (-b- sqrt (b^2-4ac))/2a

The most important part of the equation is

sqrt (b^2-4ac) as this will inform of the nature of the root.

if (b^2-4ac) >0 , the roots are real and not equal

if (b^2-4ac) = 0 , the roots are repeated.

if (b^2-4ac) < 0, the roots are complex.

Hope that helps.

Answer 4

the general formula for quadratic of type ax^2 +bx + c=0
is x=[-b (+-)[b^2 - 4ac]^1/2]/2a you will get the 2 roots once by taking + sign and the other by taking - sign...other way is to factorise by the quadratic.

Answer 5

For a polynomial of form ax^2 + bx+c=0

x= -b + or - the square root of (b^2 - 4*a*c) all divided by 2*a
since the polynomial is 2nd order there are 2 roots, thus the + or -

Answer 6

Quadratic Formula

x = - b ± √b² - 4ac / 2a

- - - - - - - - - -s-

Answer 7

y = mx + b