Hi,
If i have 8 coins, and I know that 2 of them are fake. I do not know if they are lighter or heavier than the proper coins, but the 2 fakes wiegh the same. I can weigh them twice using balance scales, and have to end up with 2 piles of four coins, eack one with 1 fake coin.
Any help would be appreciated.
Thanks, Ilya
2007-02-15 01:16:19 · 3 answers · asked by mouzy93 1 in Science & Mathematics ➔ Mathematics
1. Put 2 coins on each side of the balance.
2. Put them in separate stacks.
3. Put the other 4 coins on the balance 2 on each side.
4. If both weighings balance, then put one of the second stacks on each of the first stack and you will have it.
If one balances and the other does not put one from each side of the unbalanced weighing. and you will have it.
If both are unbalanced keep each weighing together and you will have it.
2007-02-19 08:40:13 · answer #1 · answered by Catman 4 · 2⤊ 0⤋
I think the answer is in being asymetric.
Try weighing 6 coins
3 and 3
If it balances
make two piles of 3 without rearranging anything
take the 2 others and place one on each of the two piles
the task is then done
*******
If it does not balance????
there are too many options for me to work it out right now and maybe it is not possible.
The 12 coin problem with one fake coin and three weighings was solved by being asymetric in the number of coins per weighing.
2007-02-15 01:38:14 · answer #2 · answered by anonimous 6 · 0⤊ 0⤋
try taking the two fake coins and put one real one with it. K, Bye!!!!!!!!
Sinserorly
D.M
2007-02-15 01:26:49 · answer #3 · answered by D M 1 · 0⤊ 1⤋