Hi everyone, I have a few Algebra questions I have to do for a assignment..I did not study this properly because I broke my leg and was away for a while (bummer)..please if you can also explain it to me I would greatly appreciate it...
Use elimination to solve the system of equations given by 3x - 2y = 12 and 3x + 5y = 33...
A.)(6, 3)...
B.)(15, 14)....
C.)(-7, 9)...
D.)(-11, 12)...
Question 2...
Which point is a solution to the system of inequalities: y > 4x and y > -2x - 3?...
A.)(2, -200)...
B.)(0, 10)...
C.)(1, 3)...
D.)(-2, -10)..
Question 3...
Solve the system of equations given below.
5x + 4y = 25
3x + 4y = 15...
A.)(5, 0)
B.)(0, 0)
C.)(0, -5)
D.)(-5, -5)
Question 4...
Use elimination to solve the system of equations given by 10x - 4y = -20 and 10x - 5y = 35....
A.)(12, -12.5)...
B.)(50, 20)...
C.)(-24, -55)...
D.)(24, 55)...
Question 5...
Multiply: (x - 1)(x + 1)(x - 3)(x + 3)...
A.)x^4 - 10x^2 + 9...
B.)x^2 - 10x + 9...
C.)x^4 - x^2 + 3...
D.)2x^4 - 10x^2 + 19...
Thank You!
2007-02-15 00:11:55 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You'll learn more by studying this and handing in the answers late than by copying the answers. The teacher doesn't need the answers because he already knows them. What he needs is for you to learn, which you will do by studying, not by cheating.
2007-02-15 00:24:46 · answer #1 · answered by Gnomon 6 · 0⤊ 0⤋
Question 1
a) this is simple subtraction
3x - 2y = 12 (Eq1)
3x + 5y = 33 (Eq2)
Eq2 - Eq1
3x + 5y - (3x - 2y) = 33 - 12
this equates to-:
3x + 5y - 3x + 2y
7y = 21
y = 3
Sub y=3 back into Eq1
3x - 6 = 12
3x = 18
x = 6 and y = 3
Cant be mithered with 2.
Question 3
Same as Question 1
Answer is x = 5 and y = 0
Question 4 (also same method as Qu.1)
Answer is C) x = -24 and y = -55
Question 5
(x - 1) (x + 1) (x - 3) (x + 3)
x^2 - x + x - 1 (x - 3) (x + 3)
x^3 - x - 3x^2 + 3 (x + 3)
x^4 + 3x^3 - 3x - x^2 - 3x - 3x^3 - 9x^2 + 3x + 9
x^4 - 10x^2 + 9
Answer A (again!)
2007-02-15 08:32:17 · answer #2 · answered by Doctor Q 6 · 0⤊ 0⤋
3x - 2y = 12
3x + 5y = 33
~>
-3x+2y=-12
3x+5y=33
----------------
7y=21
y=21/7
y=3
5x + 4y = 25
3x + 4y = 15
~>
-5x-4y=-25
3x+4y=15
------------------
-2x=-10
x=10/2
x=5
3(5)+4y=15
15+4y=15
4y=15-15
4y=0
y=0/4
y=0
10x - 4y = -20
10x - 5y = 35
~>
-10x+4y=20
10x-5y=35
------------------
-y=55
y=-55
10x-5(-55)=35
10x+275=35
10x=35-275
10x=240
x=240/10
x=24
=(x - 1)(x + 1)(x - 3)(x + 3)
=(x^2-1)(x^2-9)
=x^4+-10x^2+9
2007-02-15 08:42:40 · answer #3 · answered by jAmPr0tzz 2 · 0⤊ 0⤋