Maths Question!!!!!!!!!!!Pls Help!!!!!!!!!!!?

Question

In a bus, there are twice as many men as women. At the next stop, 15 men alighted the bus and 15 women boarded the bus. In the end, there are thrice as many women as men. Find the number of men in the bus at first.
Pls tell me how to do and show me number statements.Pls show tables or/and models. I'm onli Pri 3.

at the 15 men alighted the bus means 15 men got off the bus

pls say in simple words

if u need divide sign put this /

Is the working like this:

12 divide 3 = 4
15 divide 5 = 3
4 multiply by 3 = 12
12 multiply by 2 = 24

do i need to add anymore steps??

Answer 1

**Link the model together**

Men and women at first:
....______ ______
M |______|______|
W|______|

After they alighted and boarded, women is thrice of men
......____
M |_:_:_|____ ____
W |_:_:_|_:_:_|_:_:_|-----------> the (:) is separating the model

So, as you can see, equal number of people boarded and alighted the bus so they should have the same number of units added and minused. So, men have three units (second model) after they went down the bus and women have 9. Before they went down the bus, the women have 4 units and the men have 8.

Why? You see from the second model, altogether there are 12 pparts or units. At first, the men have twice of women so total is 3 big units but you have 12 parts so you need to find how many parts each unit is at first. So, 12 / 3 units = 4 parts for each units.

Like I said just now, the women added 5 parts and men minused by 5 parts, so to find one part, take 15 / 5 = 3. Each part is 3.

Since you know that women increased by 5 parts of all the 9 parts, that means 4 part is what the number is before the boarded the bus. To find the original, 4 x 3 = 12.
There are 12 women on the bus at first.

To find men at first, 12 x 2 = 24 because men is twice women.

Answer 2

Let m = the initial number of men and
w = the initial number of women.

"there are twice as many men as women" that is:
m = 2w

"At the next stop, 15 men alighted the bus and 15 women boarded the bus. In the end, there are thrice as many women as men." that is
3(m-15) = w + 15


Put the value of m from the first equation into the second equation to get:
3(2w - 15) = w + 15
6w - 45 = w + 15
5w = 60
w = 12

So putting this into the first equation gives you
m=2*12 = 24.
Therefore there are 24 men and 12 women

Answer 3

In a bus, there are twice as many men as women:
m = 2w
where m for number of men at 1st and w for number of women at 1st,

At the next stop, 15 men alighted the bus and 15 women boarded the bus. In the end, there are thrice as many women as men:
(w+15) = 3 * (m - 15)

now solving the 2 equations:
(w+15) = 3 * (m - 15) but m=2w
then,
(w+15) = 3 * (2w - 15)
w+15=6w-45
5w = 60
w = 12 WOMEN
but m=2w
then, m = 24 MEN

Answer 4

Let m = the initial number of m and w = the initial number of women.

"there are twice as many men as women" tells you that:

m = 2w

"At the next stop, 15 men alighted the bus and 15 women boarded the bus. In the end, there are thrice as many women as men." tells you that:

3(m-15) = w + 15


Plug the value of m from the first equation into the second equation to get:

3(2w - 15) = w + 15
6w - 45 = w + 15
5w = 60
w = 12

So plugging this into the first equation gives you m=2*12 = 24.

Answer 5

Let M = no. of men; W = no. of women.

If there are twice as many men as women,
giving you: M = 2W

15 men alighted & 15 boarded the bus, and at the end there are thrice as many women as men,
giving you: 3(M - 15) = W + 15.

Put these 2 equation together, you have

M = 2W
3(M - 15 ) = W + 15
3 (2W - 15) = W + 15
6W - 45 = W + 15
6W - W = 45 + 15
5W = 60
W = 12
Therefore M (No. of man initially) = 2 * 12 = 24

Answer 6

You state 15 men 'alighted' the bus. Maybe you mean 15 men stepped off of the bus. Please explain.

Answer 7

Ban has given the right answer