How maybe happen if in Coulomb’s formula the exponent of ‘r’ is greater than two?

Answer 1

The stability of orbits depend on the the 1/r^2 behavior of forces for both atoms and the planets. If the exponent were not 2 atoms would not exist and we would not be here to wonder about what would happen.

Answer 2

The inverse square law 1/R^2 applies to many forces of nature, including gravity. Expressed in terms of radiating fields, the effect propages out as an expanding sphere of radius R for a point object-- the surface area of a sphere is 4piR^2 Such forces can propagate to the rest of the universe. So the exponent 2 doesn't come about casually.

In nuclear physics, where forces rapidly drop off after the nominal radius of the nucleus, inverse square law does not diminish fast enough. Usually, it is usually exponent of a negative function.

Answer 3

If the exponent of the r was bigger than 2, this would mean that the electric force (attraction or repulsion) is not as strong. It will be weaker. It will decrease as the cube of the distance for example.