how do you solve (x-1)(x^2+5x+6)=0?

Answer 1

First you take a piss.

Once you flush, you can say your ABCs. When you get to J, the toilet should be empty. J=8.

So factoring in that 8 for 'x' = you light the BBQ grill. Since a guy cannot BBQ without a beer - open a beer. Beers have 12 oz. of liquid in them.

So the answer is 12.

Answer 2

http://www.algebrahelp.com

Simplifying
(x + -1)(x2 + 5x + 6) = 0

Reorder the terms:
(-1 + x)(x2 + 5x + 6) = 0

Reorder the terms:
(-1 + x)(6 + 5x + x2) = 0

Multiply (-1 + x) * (6 + 5x + x2)
(-1(6 + 5x + x2) + x(6 + 5x + x2)) = 0
((6 * -1 + 5x * -1 + x2 * -1) + x(6 + 5x + x2)) = 0
((-6 + -5x + -1x2) + x(6 + 5x + x2)) = 0
(-6 + -5x + -1x2 + (6 * x + 5x * x + x2 * x)) = 0
(-6 + -5x + -1x2 + (6x + 5x2 + x3)) = 0

Reorder the terms:
(-6 + -5x + 6x + -1x2 + 5x2 + x3) = 0

Combine like terms: -5x + 6x = 1x
(-6 + 1x + -1x2 + 5x2 + x3) = 0

Combine like terms: -1x2 + 5x2 = 4x2
(-6 + 1x + 4x2 + x3) = 0

Solving
-6 + 1x + 4x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

Answer 3

factor out the second part
(x-1)(x+3)(x+2)=0
x-1=0; x=-1
x+3=0; x=-3
x+2=0; x=-2

answers:
x=1, x=-3, x=-2

Answer 4

(x-1)(x^2+5x+6)
=(x-1)(x^2+3x+2x+6)
=(x-1) { x(x+3)+2(x+3) }
=(x-1)(x+3)(x+2)=0

x=1, x= -3, x= -2

Answer 5

when a*b=0
that means
a=0 or b=0 or both

then x-1=0
->x=1
or
(x^2+5x+6)=0
x1=-2;x2=-3
or both

Answer 6

obviously one of the solutions is x=1. to solve the quadratic, you can either plot that on a graphing calculator or use the QUADRATIC FORMULA. i don't want to sound rude, but seriously have you not learned that in math class?? use it!

Answer 7

12.1X2.5X2.5