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integrate

x / (x+2)

2007-02-14 16:15:45 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Integral [(x / (x + 2)) dx]

One way you can solve it (I can immediately think of at least two) is to use substitution.

Let u = x + 2. Then
u - 2 = x, so
du = dx.

Making the appropriate substitution, we get

Integral [(u - 2) / u ] du

Which we can separate into two fractions.

Integral [u/u - 2/u] du

Integral [1 - 2/u] du

Integral [1 - 2(1/u)] du

Which we can now integrate directly, as

u - 2ln|u| + C

Substituting u = x + 2 back, we have

x + 2 - 2 ln |x + 2| + C

2007-02-14 16:20:45 · answer #1 · answered by Puggy 7 · 0 0

x/(x+2)

by adding 0 to the numerator (2-2) you can rewrite it as

S(x+2-2)/(x+2) dx

then you can break it into two separate integrals

S(x+2)/(x+2) dx - S2/(x+2) dx
S1 dx - 2 S 1/(x+2) dx
x - 2 ln |x+2| +C

2007-02-15 00:33:32 · answer #2 · answered by radne0 5 · 0 0

wang?
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For the release of monumental evacuations of flatulence can protect us from the upcoming ice age.
The ozone layer only wants to be our friend, so I say let him have his day in the sun (comparatively to us humanoids on planet Earth).

2007-02-15 00:25:16 · answer #3 · answered by Toilet 2 · 0 1

primitive(x / (x+2))= primitive((x+2)/(x+2)-2/(x+2))=x-2* primitive(1/(x+2))+C=x-2*ln(x+2)+C

2007-02-15 00:23:31 · answer #4 · answered by Suiram 2 · 0 0

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