44.35g KOH in 125.0 mL of solution
2007-02-14 15:59:18 · 4 answers · asked by Joe J 1 in Science & Mathematics ➔ Chemistry
44.35g KOH in 125.0 mL of solution
so the awnser is 9.90 M ?
2007-02-14 16:03:48 · update #1
M = moles/L
to get moles of KOH divide the mass by the molecular weight.
then all you have to do is convert mL to L and solve the equation for M
2007-02-14 16:02:52 · answer #1 · answered by shiara_blade 6 · 0⤊ 0⤋
Molaritity = (weight of substance/molar mass of substance) / (volume of solution/1 L)
sorry don't have a calc so you have to do the maths yourself
2007-02-14 16:03:28 · answer #2 · answered by Mr Hex Vision 7 · 0⤊ 0⤋
Molarity= moles/liters convert your garams to mols by diviging by the formula weight then divide moles by liters then you will have M
2007-02-15 02:13:22 · answer #3 · answered by Anna M 1 · 0⤊ 0⤋
44.35g KOH/ 35.99 g/mol KOH = 1.2319 mol KOH
1.2319/ 0.125 L = 9.855 M
Yep, rounded it would be 9.9 M
2007-02-14 16:06:50 · answer #4 · answered by hanovercc 2 · 0⤊ 0⤋